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2.3 Q-1

Question Statement

Differentiate the following expression with respect to xx:
Y=x4+2x3+x2Y = x^4 + 2x^3 + x^2


Background and Explanation

In this problem, we will use the power rule of differentiation, which states:
ddx[xn]=nβ‹…xnβˆ’1\frac{d}{dx} \left[ x^n \right] = n \cdot x^{n-1}
This rule allows us to quickly find the derivative of polynomial terms by multiplying the power of xx with its coefficient and reducing the power by 1.


Solution

Let the given function be: Y=x4+2x3+x2Y = x^4 + 2x^3 + x^2

Step 1: Differentiate each term

We will apply the power rule to each term of the polynomial:

  1. For x4x^4:
    ddx[x4]=4x3\frac{d}{dx} \left[ x^4 \right] = 4x^3

  2. For 2x32x^3:
    ddx[2x3]=6x2\frac{d}{dx} \left[ 2x^3 \right] = 6x^2

  3. For x2x^2:
    ddx[x2]=2x\frac{d}{dx} \left[ x^2 \right] = 2x

Step 2: Combine the derivatives

Adding all the individual derivatives together: dydx=4x3+6x2+2x\frac{dy}{dx} = 4x^3 + 6x^2 + 2x

Final Answer:
dydx=4x3+6x2+2x\frac{dy}{dx} = 4x^3 + 6x^2 + 2x


Key Formulas or Methods Used

  • Power Rule:
    ddx[xn]=nβ‹…xnβˆ’1\frac{d}{dx} \left[ x^n \right] = n \cdot x^{n-1}

Summary of Steps

  1. Identify the given function:
    Y=x4+2x3+x2Y = x^4 + 2x^3 + x^2

  2. Apply the power rule to differentiate each term:

    • ddx[x4]=4x3\frac{d}{dx} \left[ x^4 \right] = 4x^3
    • ddx[2x3]=6x2\frac{d}{dx} \left[ 2x^3 \right] = 6x^2
    • ddx[x2]=2x\frac{d}{dx} \left[ x^2 \right] = 2x
  3. Combine the results to find the derivative:
    dydx=4x3+6x2+2x\frac{dy}{dx} = 4x^3 + 6x^2 + 2x

This gives the rate of change of the function YY with respect to xx.