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3.3 Q-13

Question Statement

Evaluate the following integral:

axa2x4,dx\int \frac{a x}{\sqrt{a^2 - x^4}} , dx

Background and Explanation

This problem involves the integration of a rational function containing a square root. To solve this, we will apply a substitution and trigonometric identities to simplify the expression into a more manageable form. The key steps involve recognizing the structure and transforming the integral using a substitution for easier integration.


Solution

Let’s solve the integral step by step:

  1. Rewrite the Integral: The given integral is:
axa2x4,dx \int \frac{a x}{\sqrt{a^2 - x^4}} , dx

We notice that x4x^4 can be written as (x2)2(x^2)^2. So, the integral becomes:

axa2(x2)2,dx \int \frac{a x}{\sqrt{a^2 - (x^2)^2}} , dx
  1. Substitute with Trigonometric Identity: To simplify, we use a trigonometric substitution. Let:
x2=asinθ x^2 = a \sin \theta

which implies that:

2x,dx=acosθ,dθ 2 x , dx = a \cos \theta , d\theta
  1. Substitute into the Integral: Now, substitute into the integral. First, simplify the square root term:
a2x4=a2a2sin2θ=acosθ \sqrt{a^2 - x^4} = \sqrt{a^2 - a^2 \sin^2 \theta} = a \cos \theta

Substituting into the integral:

axacosθacosθ2,dθ \int \frac{a x}{a \cos \theta} \cdot \frac{a \cos \theta}{2} , d\theta
  1. Simplify the Expression: After substitution, the integral simplifies to:
=a21,dθ = \frac{a}{2} \int 1 , d\theta

The integral of 1 with respect to θ\theta is simply θ\theta. Therefore:

=a2θ+C = \frac{a}{2} \theta + C
  1. Substitute Back θ\theta in Terms of xx: Recall that:
sinθ=x2a \sin \theta = \frac{x^2}{a}

So the solution becomes:

=a2sin1(x2a)+C = \frac{a}{2} \sin^{-1}\left(\frac{x^2}{a}\right) + C

Key Formulas or Methods Used

  • Substitution:
    • x2=asinθx^2 = a \sin \theta, which leads to 2x,dx=acosθ,dθ2 x , dx = a \cos \theta , d\theta.
  • Trigonometric Identity:
    • a2x4=acosθ\sqrt{a^2 - x^4} = a \cos \theta.
  • Inverse Trigonometric Function:
    • The integral of 1 with respect to θ\theta is θ\theta, and we use sinθ=x2a\sin \theta = \frac{x^2}{a} to find the solution in terms of xx.

Summary of Steps

  1. Rewrite the integral using x4=(x2)2x^4 = (x^2)^2.
  2. Use the substitution x2=asinθx^2 = a \sin \theta, and simplify the square root term.
  3. Substitute into the integral and simplify the expression.
  4. Integrate and then substitute back sinθ=x2a\sin \theta = \frac{x^2}{a} to express the result in terms of xx.
  5. The final result is:
a2sin1(x2a)+C \frac{a}{2} \sin^{-1}\left(\frac{x^2}{a}\right) + C