π¨ This site is a work in progress. Exciting updates are coming soon!
3.3 Q-19
Question Statement
Evaluate the following integral:
β«[cos(xββ2xβ)]Γ[xβ1ββ1],dx
Background and Explanation
To solve this integral, we will use a substitution method to simplify the expression. The integrand consists of a cosine function multiplied by a rational expression. A useful substitution will make the cosine function easier to handle and transform the integral into a simpler form.
Solution
Letβs solve the integral step by step:
Substitution:
We begin by setting the expression inside the cosine function as a new variable:
xββ2xβ=u
Now, differentiate both sides with respect to x:
dxdβ(xββ2xβ)=2xβ1ββ21β
Therefore, the differential dx becomes:
dx=2,du
Transform the Integral:
Substituting u=xββ2xβ into the original integral, we also replace the differential dx as 2,du. The term xβ1ββ1 becomes part of du, so we have: