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3.3 Q-9
Question Statement
Evaluate the following integral:
∫(1+x2)23dx
Background and Explanation
To solve this problem, we need to recognize a standard integral form that can be simplified using a trigonometric substitution. The key concepts involved include:
Trigonometric substitution: Using the identity 1+tan2θ=sec2θ to simplify the integrand.
Basic trigonometric identities: Such as sec2θ=1+tan2θ and cosθ=secθ1.
Solution
Let’s solve this step by step:
Substitute using trigonometric identities:
We choose the substitution:
x=tanθ
Then, we differentiate to get:
dx=sec2θ,dθ
Rewrite the integral:
Substituting x=tanθ into the original integral, we get:
∫(1+x2)23dx=∫(1+tan2θ)23sec2θ,dθ
Simplify using a standard trigonometric identity:
Recall that:
1+tan2θ=sec2θ
Thus, the integral becomes:
=∫(sec2θ)23sec2θ,dθ=∫sec3θsec2θ,dθ
Simplify further:
We can now cancel out one factor of secθ from the numerator and denominator:
=∫secθdθ=∫cosθ,dθ
Integrate:
The integral of cosθ is straightforward:
∫cosθ,dθ=sinθ+C
Substitute back in terms of x:
Recall that x=tanθ, so we can express sinθ in terms of x:
sinθ=1−1+x21=1+x2x
Final result:
Therefore, the integral evaluates to:
∫(1+x2)23dx=1+x2x+C
Key Formulas or Methods Used
Trigonometric substitution: x=tanθ
Basic trigonometric identities:
1+tan2θ=sec2θ
secθ=cosθ1
Summary of Steps
Use the substitution x=tanθ to simplify the integrand.
Simplify the integral using the identity 1+tan2θ=sec2θ.
Express the integral in terms of secθ and simplify.
Integrate cosθ to get sinθ+C.
Substitute back to express the result in terms of x.