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3.6 Q-12
Question Statement
Evaluate the integral:
β«12β(x+x1β)21β(1βx21β),dx
Background and Explanation
This is an integral involving a rational expression with a square root and a term involving x21β. To simplify this integral, weβll use substitution to convert it into a more manageable form. Specifically, we will let:
y=x+x1β
This substitution will simplify the integrand and allow us to proceed with the integration.
Solution
Substitute the Expression:
Let:
y=x+x1β
Now, differentiate with respect to x to find dy:
dy=(1βx21β)dx
Adjust Limits of Integration:
When x=1, we get:
y=1+11β=2
When x=2, we get:
y=2+21β=25β
Thus, the limits for y change from x=1 to x=2, corresponding to y=2 to y=25β.
Rewrite the Integral:
Substitute into the original integral:
β«12β(x+x1β)21β(1βx21β)dx
becomes:
β«225ββy21β,dy
Integrate:
Now, integrate the function y21β with respect to y. The formula for the integral of yn is:
β«yn,dy=n+1yn+1β
In this case, n=21β, so:
β«y21β,dy=32βy23β
Evaluate the Integral:
Now, substitute the limits 25β and 2 into the antiderivative:
32β[y23β]225ββ
This becomes:
32β[(25β)23ββ223β]
Simplify the Result:
Now simplify the expression:
32β[223β523βββ223β]
Factor out 32β2β to make the expression easier to handle:
32β2β[55ββ8]
Thus, the value of the integral is:
32β2β[55ββ8]β
Key Formulas or Methods Used
Substitution:
y=x+x1βdy=(1βx21β)dx
Integral of a Power:
β«yn,dy=n+1yn+1β
Summary of Steps
Let y=x+x1β, and differentiate to get dy=(1βx21β)dx.
Change the limits of integration: when x=1, y=2; and when x=2, y=25β.
Substitute into the integral and simplify it to β«225ββy21β,dy.
Integrate using the formula β«yn,dy=n+1yn+1β to get 32βy23β.
Evaluate the result at the limits to get:
32β2β[55ββ8]