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4.1 Q-14

Question Statement

Find the point that is three-fifths of the way along the line segment from A(βˆ’5,8)A(-5, 8) to B(5,3)B(5, 3).


Background and Explanation

To solve this problem, we need to find the coordinates of a point that divides the line segment between two points in a specific ratio. The formula used for this is the section formula, which helps determine the coordinates of a point dividing a line segment in a given ratio.

Here, the ratio is 3:2 (since three-fifths of the way means the ratio of distances between the point and the endpoints is 3:2).


Solution

We are given the points A(βˆ’5,8)A(-5, 8) and B(5,3)B(5, 3), and we need to find the point that divides the segment in a 3:2 ratio.

Step 1: Use the Section Formula for the xx-coordinate

The section formula for a point dividing a line segment in the ratio m:nm:n is given by:

x=nx1+mx2m+nx = \frac{n x_1 + m x_2}{m + n}

For the point dividing the segment in a 3:2 ratio, we substitute the following values:

  • x1=βˆ’5x_1 = -5 (coordinate of point AA)
  • x2=5x_2 = 5 (coordinate of point BB)
  • m=3m = 3, n=2n = 2

Now, we calculate the xx-coordinate:

x=3(5)+2(βˆ’5)3+2=15βˆ’105=55=1x = \frac{3(5) + 2(-5)}{3 + 2} = \frac{15 - 10}{5} = \frac{5}{5} = 1

So, the xx-coordinate of the point is 1.


Step 2: Use the Section Formula for the yy-coordinate

Similarly, we use the section formula for the yy-coordinate:

y=ny1+my2m+ny = \frac{n y_1 + m y_2}{m + n}

Substitute the values for the coordinates of AA and BB:

  • y1=8y_1 = 8 (coordinate of point AA)
  • y2=3y_2 = 3 (coordinate of point BB)
  • m=3m = 3, n=2n = 2

Now, we calculate the yy-coordinate:

y=3(3)+2(8)3+2=9+165=255=5y = \frac{3(3) + 2(8)}{3 + 2} = \frac{9 + 16}{5} = \frac{25}{5} = 5

So, the yy-coordinate of the point is 5.


Thus, the point that is three-fifths of the way along the line segment is C(1,5)C(1, 5).


Key Formulas or Methods Used

  • Section Formula:
    For a point dividing a line segment in the ratio m:nm:n, the coordinates of the point are given by:
x=nx1+mx2m+n,y=ny1+my2m+n x = \frac{n x_1 + m x_2}{m + n}, \quad y = \frac{n y_1 + m y_2}{m + n}

Summary of Steps

  1. Apply the section formula for the xx-coordinate using the ratio 3:2.
  2. Apply the section formula for the yy-coordinate using the ratio 3:2.
  3. The point dividing the segment is C(1,5)C(1, 5).