Question Statement
Find the value of h such that the points A(β1,h), B(3,2), and C(7,3) are collinear.
Background and Explanation
To determine if three points are collinear (lie on the same straight line), we can use the concept of the area of the triangle formed by these points. If the area is zero, the points are collinear. This can be calculated using a determinant-based formula for the area of a triangle. If the area is zero, the points are collinear.
For three points A(x1β,y1β), B(x2β,y2β), and C(x3β,y3β), the area of the triangle formed by them is given by:
Area=21ββ£x1β(y2ββy3β)+x2β(y3ββy1β)+x3β(y1ββy2β)β£
For the points to be collinear, the area must be zero.
Solution
We are given the points A(β1,h), B(3,2), and C(7,3). Using the formula for the area of a triangle, we substitute the coordinates of the points:
Area=21ββ£β1(2β3)+3(3βh)+7(hβ2)β£
For the points to be collinear, the area must be zero:
21ββ£β1(2β3)+3(3βh)+7(hβ2)β£=0
This simplifies to:
β£β1(2β3)+3(3βh)+7(hβ2)β£=0
Step 2: Simplify the Expression
Now, expand the terms inside the absolute value:
β£β1(β1)+3(3βh)+7(hβ2)β£=0
Simplify each term:
β£1+9β3h+7hβ14β£=0
Combine like terms:
β£1+9β14+(7hβ3h)β£=0
β£β4+4hβ£=0
Step 3: Solve for h
For the absolute value to be zero, the expression inside must also be zero:
β4+4h=0
Solving for h:
4h=4
h=1
Thus, the value of h is 1.
- Collinearity Condition: The points are collinear if the area of the triangle they form is zero. The area is given by the formula:
Area=21ββ£x1β(y2ββy3β)+x2β(y3ββy1β)+x3β(y1ββy2β)β£
Summary of Steps
- Use the formula for the area of a triangle formed by three points.
- Substitute the coordinates of the points A(β1,h), B(3,2), and C(7,3).
- Simplify the resulting equation.
- Set the expression inside the absolute value to zero.
- Solve for h, which gives h=1.