Skip to content
🚨 This site is a work in progress. Exciting updates are coming soon!

4.3 Q-28

Question Statement

Determine whether the given points lie above or below the specified lines.

  • Part (a): Point (5,8)(5,8) and line 2xβˆ’3y+6=02x - 3y + 6 = 0.
  • Part (b): Point (βˆ’7,6)(-7,6) and line 4x+3yβˆ’9=04x + 3y - 9 = 0.

Background and Explanation

To check whether a point lies above or below a line, substitute the coordinates of the point into the line’s equation. This results in a value on the left-hand side (LHS):

  • If the LHS is positive, the point is above the line.
  • If the LHS is negative, the point is below the line.
  • If the LHS equals zero, the point lies on the line.

The sign of the coefficient of yy determines whether the result aligns with the concept of β€œabove” or β€œbelow.”


Solution

Part (a): Point (5,8)(5,8) and line 2xβˆ’3y+6=02x - 3y + 6 = 0

  1. Line Equation:
2xβˆ’3y+6=0(1) 2x - 3y + 6 = 0 \tag{1}
  1. Substitute the point (5,8)(5,8) into the LHS of the equation:
LHS=2(5)βˆ’3(8)+6 \text{LHS} = 2(5) - 3(8) + 6

Simplifying step-by-step:

LHS=10βˆ’24+6 \text{LHS} = 10 - 24 + 6 LHS=βˆ’8 \text{LHS} = -8
  1. Since the result is negative and the coefficient of yy is negative in the equation, the point lies above the line.

Part (b): Point (βˆ’7,6)(-7,6) and line 4x+3yβˆ’9=04x + 3y - 9 = 0

  1. Line Equation:
4x+3yβˆ’9=0(2) 4x + 3y - 9 = 0 \tag{2}
  1. Substitute the point (βˆ’7,6)(-7,6) into the LHS of the equation:
LHS=4(βˆ’7)+3(6)βˆ’9 \text{LHS} = 4(-7) + 3(6) - 9

Simplifying step-by-step:

LHS=βˆ’28+18βˆ’9 \text{LHS} = -28 + 18 - 9 LHS=βˆ’19 \text{LHS} = -19
  1. Since the result is negative and the coefficient of yy is positive in the equation, the point lies below the line.

Key Formulas or Methods Used

  • Line Equation: ax+by+c=0ax + by + c = 0
  • Substitution of point (x,y)(x, y) into the line equation.
  • Sign Analysis:
    • LHS > 0: Point lies above the line.
    • LHS < 0: Point lies below the line.
    • LHS = 0: Point lies on the line.

Summary of Steps

  1. Write the equation of the line.
  2. Substitute the coordinates of the given point into the LHS of the equation.
  3. Simplify the expression to find the result.
  4. Compare the sign of the result with the coefficient of yy:
    • Same signs: Above the line.
    • Opposite signs: Below the line.