Question Statement
Find the condition that the lines y=m1βx+c1β, y=m2βx+c2β, and y=m3βx+c3β are concurrent.
That is, determine the relationship between the slopes and intercepts of these lines for them to intersect at a single point.
Background and Explanation
In geometry, three lines are said to be concurrent if they all meet at a single point. To solve for the condition of concurrency, we need to find the relationship between the constants m1β,m2β,m3β (slopes) and c1β,c2β,c3β (intercepts) of the three given lines.
The approach involves solving a system of equations for x and y, the coordinates of the intersection point. The lines are represented by their general equations, and we aim to derive a condition under which all three equations are satisfied simultaneously.
Solution
We are given three equations of straight lines:
- m1βxβy+c1β=0
- m2βxβy+c2β=0
- m3βxβy+c3β=0
Step 1: Solve for the intersection of the first two lines
From the first two equations, we can solve for x and y.
Starting with the first and second equations:
m1βxβy+c1β=0(1)
m2βxβy+c2β=0(2)
Subtract equation (2) from equation (1):
(m1βxβy+c1β)β(m2βxβy+c2β)=0
Simplifying:
(m1ββm2β)x+(c1ββc2β)=0
Solving for x:
x=m1ββm2βc2ββc1ββ(3)
Step 2: Substitute into one of the original equations to find y
Now substitute the value of x from equation (3) into either of the original equations (letβs use equation (1)):
m1β(m1ββm2βc2ββc1ββ)βy+c1β=0
Solving for y:
y=m1ββm2βm1β(c2ββc1β)β+c1β
Thus, the coordinates of the intersection of the first two lines are:
x=m1ββm2βc2ββc1ββ,y=m1ββm2βm1β(c2ββc1β)β+c1β
Step 3: Substitute these into the third equation
Now, substitute x and y into the third equation m3βxβy+c3β=0:
m3β(m1ββm2βc2ββc1ββ)β(m1ββm2βm1β(c2ββc1β)β+c1β)+c3β=0
Simplify the equation to find the condition for concurrency:
m3β(c2ββc1β)βm2βc1ββm1βc2β+m2βc3ββm1βc3β=0
Rearranging terms:
m3β(c2ββc1β)+m2β(c3ββc1β)+m1β(c1ββc3β)=0
Step 4: Final condition for concurrency
Thus, the condition for the three lines to be concurrent is:
(m2ββm1β)(c3ββc1β)=(m3ββm1β)(c2ββc1β)
- Equation of a line: y=mx+c
- Solving a system of linear equations
- Condition for three lines to be concurrent
Summary of Steps
- Write the equations of the three lines.
- Solve for x and y using the first two lines.
- Substitute x and y into the third lineβs equation.
- Simplify to find the condition for concurrency:
(m2ββm1β)(c3ββc1β)=(m3ββm1β)(c2ββc1β)