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5.1 Q-1

Question Statement

Graph the solution set of the following linear inequalities in the xyxy-plane:

i. 2x+y62x + y \leq 6

ii. 3x+7y213x + 7y \geq 21

iii. 3x2y63x - 2y \geq 6

iv. 5x4y205x - 4y \leq 20

v. 2x+102x + 1 \geq 0

vi. 3y403y - 4 \geq 0


Background and Explanation

To solve linear inequalities graphically, we first convert each inequality into an equation by replacing the inequality symbol with an equal sign. The equation represents a line on the xyxy-plane, and the inequality defines which side of the line is included in the solution set.

To determine which side of the line is the solution region, we test a point, typically (0,0)(0, 0), and check if it satisfies the inequality.


Solution

i. 2x+y62x + y \leq 6

  1. Convert the inequality into an equation:
    2x+y=62x + y = 6

  2. Find two points on the line:

    • When x=0x = 0, solve for yy:
      2(0)+y=6y=6so the point is (0,6)2(0) + y = 6 \quad \Rightarrow \quad y = 6 \quad \text{so the point is } (0, 6)
    • When y=0y = 0, solve for xx:
      2x+0=6x=3so the point is (3,0)2x + 0 = 6 \quad \Rightarrow \quad x = 3 \quad \text{so the point is } (3, 0)
  3. Test the inequality at (0,0)(0, 0):
    2(0)+0=006which is true.2(0) + 0 = 0 \quad \Rightarrow \quad 0 \leq 6 \quad \text{which is true.}
    So, the region below the line 2x+y=62x + y = 6 is the solution set.


ii. 3x+7y213x + 7y \geq 21

  1. Convert the inequality into an equation:
    3x+7y=213x + 7y = 21

  2. Find two points on the line:

    • When x=0x = 0, solve for yy:
      3(0)+7y=21y=3so the point is (0,3)3(0) + 7y = 21 \quad \Rightarrow \quad y = 3 \quad \text{so the point is } (0, 3)
    • When y=0y = 0, solve for xx:
      3x+0=21x=7so the point is (7,0)3x + 0 = 21 \quad \Rightarrow \quad x = 7 \quad \text{so the point is } (7, 0)
  3. Test the inequality at (0,0)(0, 0):
    3(0)+7(0)=0021which is false.3(0) + 7(0) = 0 \quad \Rightarrow \quad 0 \geq 21 \quad \text{which is false.}
    So, the region above the line 3x+7y=213x + 7y = 21 is the solution set.


iii. 3x2y63x - 2y \geq 6

  1. Convert the inequality into an equation:
    3x2y=63x - 2y = 6

  2. Find two points on the line:

    • When x=0x = 0, solve for yy:
      3(0)2y=62y=6y=3so the point is (0,3)3(0) - 2y = 6 \quad \Rightarrow \quad -2y = 6 \quad \Rightarrow \quad y = -3 \quad \text{so the point is } (0, -3)
    • When y=0y = 0, solve for xx:
      3x0=6x=2so the point is (2,0)3x - 0 = 6 \quad \Rightarrow \quad x = 2 \quad \text{so the point is } (2, 0)
  3. Test the inequality at (0,0)(0, 0):
    3(0)2(0)=006which is false.3(0) - 2(0) = 0 \quad \Rightarrow \quad 0 \geq 6 \quad \text{which is false.}
    So, the region above the line 3x2y=63x - 2y = 6 is the solution set.


iv. 5x4y205x - 4y \leq 20

  1. Convert the inequality into an equation:
    5x4y=205x - 4y = 20

  2. Find two points on the line:

    • When x=0x = 0, solve for yy:
      5(0)4y=204y=20y=5so the point is (0,5)5(0) - 4y = 20 \quad \Rightarrow \quad -4y = 20 \quad \Rightarrow \quad y = -5 \quad \text{so the point is } (0, 5)
    • When y=0y = 0, solve for xx:
      5x0=20x=4so the point is (4,0)5x - 0 = 20 \quad \Rightarrow \quad x = 4 \quad \text{so the point is } (4, 0)
  3. Test the inequality at (0,0)(0, 0):
    5(0)4(0)=0020which is true.5(0) - 4(0) = 0 \quad \Rightarrow \quad 0 \leq 20 \quad \text{which is true.}
    So, the region below the line 5x4y=205x - 4y = 20 is the solution set.


v. 2x+102x + 1 \geq 0

  1. Convert the inequality into an equation:
    2x+1=02x + 1 = 0

  2. Solve for xx:
    2x=1x=122x = -1 \quad \Rightarrow \quad x = -\frac{1}{2}

  3. Test the inequality at (0,0)(0, 0):
    2(0)+1=110which is true.2(0) + 1 = 1 \quad \Rightarrow \quad 1 \geq 0 \quad \text{which is true.}
    So, the region to the right of the line 2x+1=02x + 1 = 0 is the solution set.


vi. 3y403y - 4 \geq 0

  1. Convert the inequality into an equation:
    3y4=03y - 4 = 0

  2. Solve for yy:
    3y=4y=433y = 4 \quad \Rightarrow \quad y = \frac{4}{3}

  3. Test the inequality at (0,0)(0, 0):
    3(0)4=440which is false.3(0) - 4 = -4 \quad \Rightarrow \quad -4 \geq 0 \quad \text{which is false.}
    So, the region above the line 3y4=03y - 4 = 0 is the solution set.


Key Formulas or Methods Used

  • Linear inequality: When solving linear inequalities, first convert the inequality into an equation to graph the boundary line.
  • Test point method: After plotting the boundary line, use a test point (typically (0,0)(0, 0)) to determine which side of the line satisfies the inequality.
  • Solution region: Depending on whether the inequality is \leq, \geq, <<, or >>, shade the appropriate region of the plane.

Summary of Steps

  1. Convert each inequality into an equation.
  2. Find two points that lie on the line.
  3. Plot these points and draw the line.
  4. Test the inequality using a point, usually (0,0)(0, 0), to determine the region that satisfies the inequality.
  5. Shade the appropriate region based on the inequality symbol.