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5.3 Q-2

Question Statement

Maximize the function f(x,y)=x+yf(x, y) = x + y subject to the constraints:

2y+5x≀302y + 5x \leq 30 5x+4y≀205x + 4y \leq 20 xβ‰₯0,yβ‰₯0x \geq 0, \quad y \geq 0

Background and Explanation

To solve this problem, we are dealing with a linear programming optimization problem. The objective is to maximize the function f(x,y)=x+yf(x, y) = x + y under the given constraints. The constraints define a feasible region, and we will use graphical methods to determine the maximum value of the objective function within this region.


Solution

Step 1: Convert constraints into equations

We first work with the two inequalities by converting them into equalities to identify boundary lines.
For the first inequality, 2y+5x≀302y + 5x \leq 30:

2xβˆ’5y=302x - 5y = 30

For the second inequality, 5x+4y≀205x + 4y \leq 20:

5xβˆ’4y=205x - 4y = 20

Step 2: Find the intersection points for each equation

We substitute x=0x = 0 and y=0y = 0 into the equations to find points of intersection:

For the first equation 2xβˆ’5y=302x - 5y = 30:

  • When x=0x = 0, 5y=30β‡’y=65y = 30 \Rightarrow y = 6. Hence, the point is (0,6)(0, 6).
  • When y=0y = 0, 2x=30β‡’x=152x = 30 \Rightarrow x = 15. Hence, the point is (15,0)(15, 0).

For the second equation 5xβˆ’4y=205x - 4y = 20:

  • When x=0x = 0, βˆ’4y=20β‡’y=5-4y = 20 \Rightarrow y = 5. Hence, the point is (0,5)(0, 5).
  • When y=0y = 0, 5x=20β‡’x=45x = 20 \Rightarrow x = 4. Hence, the point is (4,0)(4, 0).

Step 3: Determine feasibility of the region

We check if the points (0,0)(0,0), (4,0)(4,0), and (0,5)(0,5) satisfy the original constraints.

  • Substituting (0,0)(0,0) into both equations shows that the inequalities hold true.
  • Substituting (4,0)(4,0) into both equations also satisfies the inequalities.
  • Substituting (0,5)(0,5) shows that the inequalities are true as well.

Thus, these points are valid and form the feasible region. The graph below shows the shaded region where these points lie.

Graph showing the feasible region


Key Formulas or Methods Used

  • Constraints conversion into equalities to find boundary lines.
  • Substitution method to find intersection points of the constraints.
  • Feasibility check to ensure that the intersection points satisfy all constraints.

Summary of Steps

  1. Convert the inequalities into equations:
    2xβˆ’5y=30and5xβˆ’4y=202x - 5y = 30 \quad \text{and} \quad 5x - 4y = 20

  2. Find the intersection points for each equation by substituting x=0x = 0 and y=0y = 0:

    • For 2xβˆ’5y=302x - 5y = 30: (0,6)(0,6) and (15,0)(15,0).
    • For 5xβˆ’4y=205x - 4y = 20: (0,5)(0,5) and (4,0)(4,0).
  3. Check the feasibility of the region formed by the points (0,0)(0,0), (4,0)(4,0), and (0,5)(0,5).

  4. Evaluate the objective function f(x,y)=x+yf(x, y) = x + y at the corner points:

    • At (4,0)(4,0), f(4,0)=4f(4,0) = 4.
    • At (0,5)(0,5), f(0,5)=15f(0,5) = 15.
    • At (0,0)(0,0), f(0,0)=0f(0,0) = 0.
  5. The maximum value of the function is 15, occurring at the point (0,5)(0,5).