6.1 Q-5
Question Statement
Find the equation of a circle with the following conditions:
- The radius is .
- The circle lies in the second quadrant and is tangent to both the - and -axes.
Background and Explanation
To solve this problem, we need to recall the general equation of a circle:
Where:
- is the center of the circle.
- is the radius.
The key insight here is that the circle is tangent to both axes and lies in the second quadrant. This means that the center of the circle must be at a point where both the -coordinate and -coordinate are negative. Specifically, the center will be at , because the distance from the center to the axes is equal to the radius , and the circle is tangent to both axes.
Solution
Step 1: Understanding the Center and Radius
Since the circle is tangent to both axes and lies in the second quadrant, the center must be at and the radius is .
Step 2: Using the General Equation of a Circle
The general equation of a circle is:
Substituting , , and , the equation becomes:
Step 3: Expanding the Equation
Next, expand both terms in the equation:
Substitute these into equation (1):
Step 4: Simplifying the Equation
Combine like terms:
Now, move the constant to the right side:
Thus, the equation of the circle is:
Key Formulas or Methods Used
-
General Equation of a Circle:
Where is the center and is the radius. -
Expansion of Squared Terms:
Expand and to get the terms involving , , and constants. -
Simplification:
Combine like terms to obtain the final equation of the circle.
Summary of Steps
- Step 1: Identify the center and radius of the circle based on the given conditions.
- Step 2: Substitute the values for , , and into the general equation of a circle.
- Step 3: Expand both squared terms and simplify.
- Step 4: Simplify the equation further to obtain the final form.