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6.2 Q-4

Question Statement

Find the length of the tangent drawn from the point (−5,4)(-5,4) to the circle given by the equation:

5x2+5y2−10x+15y−131=05x^2 + 5y^2 - 10x + 15y - 131 = 0

Background and Explanation

To solve this problem, we need to recall the formula for the length of a tangent drawn from a point (x1,y1)(x_1, y_1) to a circle. The general equation of a circle is:

x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0

The length of the tangent from a point (x1,y1)(x_1, y_1) to the circle is given by the formula:

Length of Tangent=x12+y12−2gx1−2fy1+c\text{Length of Tangent} = \sqrt{x_1^2 + y_1^2 - 2gx_1 - 2fy_1 + c}

Where:

  • gg, ff, and cc are the coefficients from the standard form of the circle equation.
  • (x1,y1)(x_1, y_1) is the point outside the circle.

Solution

We begin by simplifying the given equation of the circle:

5x2+5y2−10x+15y−131=05x^2 + 5y^2 - 10x + 15y - 131 = 0

Divide through by 5 to simplify:

x2+y2−2x+3y−1315=0x^2 + y^2 - 2x + 3y - \frac{131}{5} = 0

From this, we identify the coefficients:

  • g=−1g = -1
  • f=32f = \frac{3}{2}
  • c=−1315c = -\frac{131}{5}

Now, using the formula for the length of the tangent:

Length of Tangent=(−5)2+42−2(−5)+3(4)−1315\text{Length of Tangent} = \sqrt{(-5)^2 + 4^2 - 2(-5) + 3(4) - \frac{131}{5}}

We break this into parts:

  1. (−5)2=25(-5)^2 = 25
  2. 42=164^2 = 16
  3. −2(−5)=10-2(-5) = 10
  4. 3(4)=123(4) = 12

Substituting these values back into the equation:

Length of Tangent=25+16+10+12−1315\text{Length of Tangent} = \sqrt{25 + 16 + 10 + 12 - \frac{131}{5}}

Simplify further:

Length of Tangent=63−1315\text{Length of Tangent} = \sqrt{63 - \frac{131}{5}}

Now, to combine the terms under the square root:

63=315563 = \frac{315}{5}

Thus:

Length of Tangent=315−1315=1845\text{Length of Tangent} = \sqrt{\frac{315 - 131}{5}} = \sqrt{\frac{184}{5}}

This is the exact length of the tangent.


Key Formulas or Methods Used

  • Formula for Length of Tangent:
Length of Tangent=x12+y12−2gx1−2fy1+c \text{Length of Tangent} = \sqrt{x_1^2 + y_1^2 - 2gx_1 - 2fy_1 + c}
  • Standard form of a circle:
x2+y2+2gx+2fy+c=0 x^2 + y^2 + 2gx + 2fy + c = 0

Summary of Steps

  1. Write the given circle equation in the standard form by dividing through by 5.
  2. Identify the values of gg, ff, and cc.
  3. Apply the formula for the length of the tangent using the given point (−5,4)(-5, 4).
  4. Simplify the expression step by step.
  5. Final result:
Length of Tangent=1845 \text{Length of Tangent} = \sqrt{\frac{184}{5}}