Skip to content
🚨 This site is a work in progress. Exciting updates are coming soon!

6.5 Q-9

Question Statement

The moon orbits the Earth in an elliptical path with Earth at one focus. The major and minor axes of the moon’s orbit are given as 786,806,km786,806 , \text{km} and 767,746,km767,746 , \text{km}, respectively. Determine the apogee (greatest distance) and perigee (least distance) of the moon from Earth.


Background and Explanation

In an elliptical orbit:

  • The major axis corresponds to the longest diameter of the ellipse, and half of it (aa) is the semi-major axis.
  • The minor axis corresponds to the shortest diameter, and half of it (bb) is the semi-minor axis.
  • The distance from the center to the focus (cc) is related to the eccentricity (ee) by c=aec = a e.
  • The apogee (farthest distance) is calculated as a+ca + c, while the perigee (nearest distance) is aca - c.

Solution

Step 1: Identify given data

  • Total major axis 2a=786,806,km2a = 786,806 , \text{km}a=786,8062=384,403,kma = \frac{786,806}{2} = 384,403 , \text{km}.
  • Total minor axis 2b=767,746,km2b = 767,746 , \text{km}b=767,7462=383,873,kmb = \frac{767,746}{2} = 383,873 , \text{km}.

Step 2: Calculate cc, the distance from the center to the focus

From the ellipse equation, c2=a2b2c^2 = a^2 - b^2:

  1. Calculate a2a^2:
a2=384,4032=147,765,666,409,km2. a^2 = 384,403^2 = 147,765,666,409 , \text{km}^2.
  1. Calculate b2b^2:
b2=383,8732=147,358,480,129,km2. b^2 = 383,873^2 = 147,358,480,129 , \text{km}^2.
  1. Compute c2c^2:
c2=a2b2=147,765,666,409147,358,480,129=407,186,280,km2. c^2 = a^2 - b^2 = 147,765,666,409 - 147,358,480,129 = 407,186,280 , \text{km}^2.
  1. Solve for cc:
c=407,186,28020,178.86,km. c = \sqrt{407,186,280} \approx 20,178.86 , \text{km}.

Step 3: Calculate the apogee and perigee

  1. Apogee (greatest distance):
Apogee=a+c=384,403+20,178.86404,582,km. \text{Apogee} = a + c = 384,403 + 20,178.86 \approx 404,582 , \text{km}.
  1. Perigee (least distance):
Perigee=ac=384,40320,178.86364,224,km. \text{Perigee} = a - c = 384,403 - 20,178.86 \approx 364,224 , \text{km}.

Key Formulas or Methods Used

  1. Semi-Major and Semi-Minor Axes:
a=Major Axis2,b=Minor Axis2. a = \frac{\text{Major Axis}}{2}, \quad b = \frac{\text{Minor Axis}}{2}.
  1. Distance from Center to Focus:
c2=a2b2. c^2 = a^2 - b^2.
  1. Apogee and Perigee:
Apogee=a+c,Perigee=ac. \text{Apogee} = a + c, \quad \text{Perigee} = a - c.

Summary of Steps

  1. Extract data: a=384,403,km,b=383,873,kma = 384,403 , \text{km}, b = 383,873 , \text{km}.
  2. Compute c2=a2b2c^2 = a^2 - b^2, giving c=20,178.86,kmc = 20,178.86 , \text{km}.
  3. Calculate apogee a+c=404,582,kma + c = 404,582 , \text{km}.
  4. Calculate perigee ac=364,224,kma - c = 364,224 , \text{km}.

Final Answer

  • Apogee: 404,582,km\mathbf{404,582 , \text{km}}.
  • Perigee: 364,224,km\mathbf{364,224 , \text{km}}.