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7.1 Q-1

Question Statement

Write the vectors PQ\mathbf{P Q} in the form xi+yj\mathbf{x i} + \mathbf{y j} for the following points:

(i) P(2,3),Q(6,βˆ’2)\quad \mathrm{P}(2,3), \mathrm{Q}(6,-2)
(ii) P(0,5),Q(βˆ’1,βˆ’6)\quad \mathrm{P}(0,5), \mathrm{Q}(-1,-6)


Background and Explanation

To solve this problem, we need to find the vector between two points. A vector is a quantity that has both magnitude and direction. The vector from point P to point Q can be calculated by subtracting the coordinates of P from the coordinates of Q.

The general form for a vector in two dimensions is:
PQ=(x2βˆ’x1)i^+(y2βˆ’y1)j^\mathbf{PQ} = (x_2 - x_1)\hat{i} + (y_2 - y_1)\hat{j}
where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of points P and Q, respectively, and i^\hat{i}, j^\hat{j} are the unit vectors in the x and y directions.


Solution

(i) P(2,3),Q(6,βˆ’2)\quad \mathrm{P}(2,3), \mathrm{Q}(6,-2)

  1. Find the components of the vector:

    • The vector from point P to point Q is calculated as:
      PQ=(6,βˆ’2)βˆ’(2,3)\mathbf{PQ} = (6, -2) - (2, 3)
  2. Subtract the corresponding coordinates:

    • Subtract the x-components:
      6βˆ’2=46 - 2 = 4
    • Subtract the y-components:
      βˆ’2βˆ’3=βˆ’5-2 - 3 = -5
  3. Write the vector in unit vector form:

    • The vector becomes:
      PQ=4i^βˆ’5j^\mathbf{PQ} = 4\hat{i} - 5\hat{j}

Thus, the vector from P to Q is:
PQ=4i^βˆ’5j^\mathbf{PQ} = 4\hat{i} - 5\hat{j}


(ii) P(0,5),Q(βˆ’1,βˆ’6)\quad \mathrm{P}(0,5), \mathrm{Q}(-1,-6)

  1. Find the components of the vector:

    • The vector from point P to point Q is:
      PQ=(βˆ’1,βˆ’6)βˆ’(0,5)\mathbf{PQ} = (-1, -6) - (0, 5)
  2. Subtract the corresponding coordinates:

    • Subtract the x-components:
      βˆ’1βˆ’0=βˆ’1-1 - 0 = -1
    • Subtract the y-components:
      βˆ’6βˆ’5=βˆ’11-6 - 5 = -11
  3. Write the vector in unit vector form:

    • The vector becomes:
      PQ=βˆ’1i^βˆ’11j^\mathbf{PQ} = -1\hat{i} - 11\hat{j}

Thus, the vector from P to Q is:
PQ=βˆ’1i^βˆ’11j^\mathbf{PQ} = -1\hat{i} - 11\hat{j}


Key Formulas or Methods Used

  • Vector from P to Q:
    PQ=(x2βˆ’x1)i^+(y2βˆ’y1)j^\mathbf{PQ} = (x_2 - x_1)\hat{i} + (y_2 - y_1)\hat{j}
    Where (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) are the coordinates of points P and Q, respectively.

Summary of Steps

  1. Identify the coordinates of points P and Q.
  2. Subtract the coordinates of P from Q to find the vector components.
  3. Express the vector in the form of unit vectors i^\hat{i} and j^\hat{j}.
  4. Simplify the vector expression if needed.