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7.1 Q-10

Question Statement

Use vectors to prove that quadrilateral ABCDA B C D is a parallelogram when the points A(0,0)A(0,0), B(a,0)B(a, 0), C(b,c)C(b, c), and D(bβˆ’a,c)D(b-a, c) are given.


Background and Explanation

To prove that a quadrilateral is a parallelogram, we need to show that both pairs of opposite sides are equal and parallel. Specifically, for quadrilateral ABCDA B C D to be a parallelogram, we need to demonstrate that:

  1. AB⃗=DC⃗A \vec{B} = D \vec{C} (Opposite sides are equal and parallel)
  2. AD⃗=BC⃗A \vec{D} = B \vec{C} (The other pair of opposite sides are equal and parallel)

We use vector subtraction to find the vectors representing the sides of the quadrilateral, then compare them to check if they satisfy the conditions for a parallelogram.


Solution

Step 1: Find the vector AB⃗A \vec{B}

  1. Coordinates of AA and BB:

    • A(0,0)A(0,0)
    • B(a,0)B(a, 0)
  2. Vector AB⃗A \vec{B}:
    ABβƒ—=(a,0)βˆ’(0,0)=(a,0)A \vec{B} = (a, 0) - (0, 0) = (a, 0)
    So, AB⃗=(a,0)A \vec{B} = (a, 0) (Equation 1).


Step 2: Find the vector DC⃗D \vec{C}

  1. Coordinates of DD and CC:

    • D(bβˆ’a,c)D(b-a, c)
    • C(b,c)C(b, c)
  2. Vector DC⃗D \vec{C}:
    DCβƒ—=(b,c)βˆ’(bβˆ’a,c)D \vec{C} = (b, c) - (b-a, c)
    Simplifying the subtraction: DCβƒ—=(bβˆ’(bβˆ’a),cβˆ’c)=(a,0)D \vec{C} = (b - (b-a), c - c) = (a, 0)
    So, DC⃗=(a,0)D \vec{C} = (a, 0). This shows that AB⃗=DC⃗A \vec{B} = D \vec{C}, confirming that opposite sides ABA B and DCD C are equal and parallel.


Step 3: Find the vector AD⃗A \vec{D}

  1. Coordinates of AA and DD:

    • A(0,0)A(0, 0)
    • D(bβˆ’a,c)D(b-a, c)
  2. Vector AD⃗A \vec{D}:
    ADβƒ—=(bβˆ’a,c)βˆ’(0,0)=(bβˆ’a,c)A \vec{D} = (b-a, c) - (0, 0) = (b-a, c)
    So, ADβƒ—=(bβˆ’a,c)A \vec{D} = (b-a, c) (Equation 3).


Step 4: Find the vector BC⃗B \vec{C}

  1. Coordinates of BB and CC:

    • B(a,0)B(a, 0)
    • C(b,c)C(b, c)
  2. Vector BC⃗B \vec{C}:
    BCβƒ—=(b,c)βˆ’(a,0)=(bβˆ’a,c)B \vec{C} = (b, c) - (a, 0) = (b-a, c)
    So, BCβƒ—=(bβˆ’a,c)B \vec{C} = (b-a, c) (Equation 4).


Step 5: Compare the vectors AD⃗A \vec{D} and BC⃗B \vec{C}

From Equations 3 and 4, we see that:
ADβƒ—=BCβƒ—=(bβˆ’a,c)A \vec{D} = B \vec{C} = (b-a, c)

This confirms that the opposite sides ADA D and BCB C are equal and parallel.


Step 6: Conclude that ABCDA B C D is a parallelogram

Since both pairs of opposite sides ABβˆ₯DCA B \parallel D C and ADβˆ₯BCA D \parallel B C, the quadrilateral ABCDA B C D satisfies the properties of a parallelogram.

Thus, ABCDA B C D is a parallelogram.


Key Formulas or Methods Used

  • Vector between two points:
    The vector from point P(x1,y1)P(x_1, y_1) to point Q(x2,y2)Q(x_2, y_2) is:
    PQβ†’=(x2βˆ’x1)i^+(y2βˆ’y1)j^\overrightarrow{P Q} = (x_2 - x_1)\hat{i} + (y_2 - y_1)\hat{j}

  • Parallelogram Property:
    Opposite sides of a parallelogram are equal and parallel. Hence:
    AB⃗=DC⃗andAD⃗=BC⃗A \vec{B} = D \vec{C} \quad \text{and} \quad A \vec{D} = B \vec{C}


Summary of Steps

  1. Find the vector AB⃗A \vec{B} using the coordinates of points AA and BB.
  2. Find the vector DC⃗D \vec{C} using the coordinates of points DD and CC.
  3. Show that AB⃗=DC⃗A \vec{B} = D \vec{C}, confirming one pair of opposite sides are equal and parallel.
  4. Find the vectors AD⃗A \vec{D} and BC⃗B \vec{C}.
  5. Show that AD⃗=BC⃗A \vec{D} = B \vec{C}, confirming the other pair of opposite sides are equal and parallel.
  6. Conclude that ABCDA B C D is a parallelogram based on the properties of parallel and equal sides.