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7.1 Q-4
Question Statement
Find the sum of vectors AB and CD, given the four points:
A(1,β1)
B(2,0)
C(β1,3)
D(β2,2)
Background and Explanation
To find the sum of vectors AB and CD, we first need to calculate the individual vectors. The vector from point A to point B is written as AB, and the vector from point C to point D is written as CD. The vector between two points P(x1β,y1β) and Q(x2β,y2β) is calculated using the formula:
PQ=(x2ββx1β)i^+(y2ββy1β)j^β
Once we have these two vectors, we add them together by combining their i and j components separately.
Solution
Step 1: Calculate AB
Find the components of AB:
The coordinates of A(1,β1) and B(2,0) give us:
AB=(2,0)β(1,β1)
Subtract the corresponding components: AB=(2β1,0+1)=i^+j^β
So, the vector AB=i^+j^β (Equation 1).
Step 2: Calculate CD
Find the components of CD:
The coordinates of C(β1,3) and D(β2,2) give us:
CD=(β2,2)β(β1,3)
Subtract the corresponding components: CD=(β2+1,2β3)=βi^βj^β
So, the vector CD=βi^βj^β (Equation 2).
Step 3: Add AB and CD
Add the two vectors: AB+CD=(i^+j^β)+(βi^βj^β)
Simplify by combining the i and j components: AB+CD=i^βi^+j^ββj^β AB+CD=0
Thus, the sum of the vectors is the null vector: AB+CD=0
Key Formulas or Methods Used
Vector between two points: PQ=(x2ββx1β)i^+(y2ββy1β)j^β
Vector addition:
To add two vectors, combine their i and j components: A+B=(x1β+x2β)i^+(y1β+y2β)j^β
Summary of Steps
Find the vector AB by subtracting the coordinates of A from B.
Find the vector CD by subtracting the coordinates of C from D.
Add the two vectors by combining their i and j components.
Simplify to find the sum of the vectors, which in this case is the null vector 0.