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7.5 Q-7

Question Statement

Find the work done when a constant force Fβ€Ύ=4i^+3j^+5k^\underline{F} = 4 \hat{i} + 3 \hat{j} + 5 \hat{k} is applied to an object, which moves from point P1(3,1,βˆ’2)P_1(3,1,-2) to point P2(2,4,6)P_2(2,4,6).


Background and Explanation

In physics, the work done by a constant force is calculated using the formula:

W=Fβ€Ύβ‹…dβ€ΎW = \underline{F} \cdot \underline{d}

Where:

  • Fβ€Ύ\underline{F} is the force vector,
  • dβ€Ύ\underline{d} is the displacement vector (the change in position).

To calculate displacement dβ€Ύ\underline{d}, subtract the initial position vector from the final position vector:

dβ€Ύ=P2βˆ’P1\underline{d} = P_2 - P_1

Then, work is the dot product of the force and displacement vectors.


Solution

We are given the force vector Fβ€Ύ=4i^+3j^+5k^\underline{F} = 4 \hat{i} + 3 \hat{j} + 5 \hat{k}, and the points P1(3,1,βˆ’2)P_1(3,1,-2) and P2(2,4,6)P_2(2,4,6).

Step 1: Find the displacement vector dβ€Ύ\underline{d}

The displacement vector is calculated by subtracting the coordinates of point P1P_1 from those of point P2P_2:

dβ€Ύ=P2βˆ’P1=(2,4,6)βˆ’(3,1,βˆ’2)\underline{d} = P_2 - P_1 = (2, 4, 6) - (3, 1, -2) dβ€Ύ=(2βˆ’3,4βˆ’1,6+2)=(βˆ’1,3,8)\underline{d} = (2-3, 4-1, 6+2) = (-1, 3, 8)

Thus, the displacement vector is:

dβ€Ύ=βˆ’i^+3j^+8k^\underline{d} = -\hat{i} + 3 \hat{j} + 8 \hat{k}

Step 2: Compute the dot product of Fβ€Ύ\underline{F} and dβ€Ύ\underline{d}

Now we calculate the work done, which is the dot product of the force vector Fβ€Ύ\underline{F} and the displacement vector dβ€Ύ\underline{d}:

W=Fβ€Ύβ‹…dβ€ΎW = \underline{F} \cdot \underline{d}

Substitute the components of the vectors:

W=(4i^+3j^+5k^)β‹…(βˆ’i^+3j^+8k^)W = (4 \hat{i} + 3 \hat{j} + 5 \hat{k}) \cdot (-\hat{i} + 3 \hat{j} + 8 \hat{k})

Now, compute the individual terms of the dot product:

W=4(βˆ’1)+3(3)+5(8)W = 4(-1) + 3(3) + 5(8) W=βˆ’4+9+40W = -4 + 9 + 40

Thus, the total work done is:

W=45,JoulesW = 45 , \text{Joules}

Key Formulas or Methods Used

  • Work Done by a Constant Force:
W=Fβ€Ύβ‹…dβ€Ύ W = \underline{F} \cdot \underline{d}

Where Fβ€Ύ\underline{F} is the force vector and dβ€Ύ\underline{d} is the displacement vector.

  • Displacement Vector:
dβ€Ύ=P2βˆ’P1 \underline{d} = P_2 - P_1

Where P1P_1 and P2P_2 are the initial and final position vectors.


Summary of Steps

  1. Find the displacement vector: Subtract the initial position vector P1P_1 from the final position vector P2P_2.
  2. Compute the dot product: Multiply corresponding components of the force and displacement vectors and sum the results.
  3. Calculate the work done: The result from the dot product gives the work done, in this case, 45,Joules45 , \text{Joules}.